What is the general solution for cos(x^2)=sin(x^2) ?

The general solution for cos(x^2)=sin(x^2) is x=(sqrt(pi+4pin))/2 ,x=-(sqrt(pi+4pin))/2

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cos(x^2)=sin(x^2)

cos (x^{2}) = sin (x^{2})

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

Solution steps

cos (x^{2}) = sin (x^{2})

Rewrite using trig identities

tan (x^{2}) = 1

General solutions for

tan (x^{2}) = 1

x^{2} = \frac{π}{4} + πn

Solve

x^{2} = \frac{π}{4} + πn : x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

\frac{cos ( - x )}{sin ( x )} = 0

5 sin (2 x) + 3 cos (2 x) = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

\frac{2 sin ( x ) cos ( x )}{cos ( x )} = 1

csc (3 θ) = sec (1 5^{\circ})

What is the general solution for cos(x^2)=sin(x^2) ?
The general solution for cos(x^2)=sin(x^2) is x=(sqrt(pi+4pin))/2 ,x=-(sqrt(pi+4pin))/2