What is the general solution for solvefor a,tan(a)-tan(b)=0 ?

The general solution for solvefor a,tan(a)-tan(b)=0 is a=arctan(tan(b))+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,tan(a)-tan(b)=0

solve for

a, tan (a) - tan (b) = 0

a = arctan (tan (b)) + πn

Solution steps

tan (a) - tan (b) = 0

Move

tan (b)

to the right side

tan (a) = tan (b)

Apply trig inverse properties

a = arctan (tan (b)) + πn

cos (x) = - cos (\frac{π}{7})

5 cos (x) - sin (x) = 1

tan (2 θ) = - 1.75

cos (x) = \frac{3}{2}, tan (x)

tan (t) = \frac{7}{24}

What is the general solution for solvefor a,tan(a)-tan(b)=0 ?
The general solution for solvefor a,tan(a)-tan(b)=0 is a=arctan(tan(b))+pin