What is the general solution for tan^2(θ)-1=0,pi<= θ<= 2pi ?

The general solution for tan^2(θ)-1=0,pi<= θ<= 2pi is θ=(5pi)/4 ,θ=(7pi)/4

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tan^2(θ)-1=0,pi<= θ<= 2pi

tan^{2} (θ) - 1 = 0, π \leq θ \leq 2 π

θ = \frac{5 π}{4}, θ = \frac{7 π}{4}

Solution steps

tan^{2} (θ) - 1 = 0, π \leq θ \leq 2 π

Solve by substitution

tan (θ) = 1, tan (θ) = - 1

tan (θ) = 1, π \leq θ \leq 2 π : θ = \frac{5 π}{4}

tan (θ) = - 1, π \leq θ \leq 2 π : θ = \frac{7 π}{4}

Combine all the solutions

θ = \frac{5 π}{4}, θ = \frac{7 π}{4}

sin (y) = - \frac{1}{2}

cos^{22} (x) - 2 sin^{2} (x) - 1 = 0

tan (θ) = \frac{3 5}{2}

sin (x + \frac{π}{2}) + cos^{2} (x) = 0

3 sin^{2} (x) - sin (x) - 4 = 0

What is the general solution for tan^2(θ)-1=0,pi<= θ<= 2pi ?
The general solution for tan^2(θ)-1=0,pi<= θ<= 2pi is θ=(5pi)/4 ,θ=(7pi)/4