What is the general solution for 1/(e^{sin(x))}=1 ?

The general solution for 1/(e^{sin(x))}=1 is x=2pin,x=pi+2pin

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1/(e^{sin(x))}=1

\frac{1}{e ^{s i n (x)}} = 1

x = 2 πn, x = π + 2 πn

Solution steps

\frac{1}{e ^{s i n (x)}} = 1

Apply exponent rules

- sin (x) = ln (1)

Solve

- sin (x) = ln (1) : sin (x) = 0

sin (x) = 0

Verify Solutions:

sin (x) = 0

True

The solution is

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

∣ cos (x) ∣ = \frac{3}{2}

tan (θ) = \frac{- 1}{3}, 0^{\circ} \leq θ \leq 36 0^{\circ}

4 cos (\frac{π}{4} (x + 3)) = 0

sin^{3} (x) = cos (x)

tan (\frac{91 π}{36}) = cos (36 0^{\circ} - x)

What is the general solution for 1/(e^{sin(x))}=1 ?
The general solution for 1/(e^{sin(x))}=1 is x=2pin,x=pi+2pin