What is the general solution for sin(9x+2)=cos(6x-7) ?

The general solution for sin(9x+2)=cos(6x-7) is x=(4pin+10+pi}{30},x=\frac{pi+4pin-18)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(9x+2)=cos(6x-7)

sin (9 x + 2) = cos (6 x - 7)

x = \frac{4 πn + 10 + π}{30}, x = \frac{π + 4 πn - 18}{6}

Solution steps

sin (9 x + 2) = cos (6 x - 7)

Rewrite using trig identities

sin (9 x + 2) = sin (\frac{π}{2} - (6 x - 7))

Apply trig inverse properties

9 x + 2 = \frac{π}{2} - (6 x - 7) + 2 πn, 9 x + 2 = π - (\frac{π}{2} - (6 x - 7)) + 2 πn

9 x + 2 = \frac{π}{2} - (6 x - 7) + 2 πn : x = \frac{4 πn + 10 + π}{30}

9 x + 2 = π - (\frac{π}{2} - (6 x - 7)) + 2 πn : x = \frac{π + 4 πn - 18}{6}

x = \frac{4 πn + 10 + π}{30}, x = \frac{π + 4 πn - 18}{6}

2 cos (3 x + \frac{π}{2}) = - 1

sin (\frac{3 θ}{2}) = 0

4 sin (\frac{π}{2} x) = 3

1 + cos (θ) = 2 cos (θ)

2 sin (x) cos (x) = - cos (x)

What is the general solution for sin(9x+2)=cos(6x-7) ?
The general solution for sin(9x+2)=cos(6x-7) is x=(4pin+10+pi}{30},x=\frac{pi+4pin-18)/6