What is the general solution for 2cos^2(w)+5cos(w)+3=0 ?

The general solution for 2cos^2(w)+5cos(w)+3=0 is w=pi+2pin

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2cos^2(w)+5cos(w)+3=0

2 cos^{2} (w) + 5 cos (w) + 3 = 0

w = π + 2 πn

Solution steps

2 cos^{2} (w) + 5 cos (w) + 3 = 0

Solve by substitution

cos (w) = - 1, cos (w) = - \frac{3}{2}

cos (w) = - 1 : w = π + 2 πn

cos (w) = - \frac{3}{2} :

No Solution

Combine all the solutions

w = π + 2 πn

tan (x) = - 135

3 cos (x) - 4 sin (x) = - 3

6 = 50 sin (x) - 15 cos (x), 0 < x < \frac{π}{2}

y, x = 3 sin (y)

\frac{tan ( θ )}{cot ( θ )} = 1

What is the general solution for 2cos^2(w)+5cos(w)+3=0 ?
The general solution for 2cos^2(w)+5cos(w)+3=0 is w=pi+2pin