What is the general solution for 3-2sin(θ)=-3+2sin(θ) ?

The general solution for 3-2sin(θ)=-3+2sin(θ) is No Solution for θ\in\mathbb{R}

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3-2sin(θ)=-3+2sin(θ)

3 - 2 sin (θ) = - 3 + 2 sin (θ)

No Solution for θ \in R

Solution steps

3 - 2 sin (θ) = - 3 + 2 sin (θ)

Solve by substitution

sin (θ) = \frac{3}{2}

sin (θ) = \frac{3}{2} :

No Solution

Combine all the solutions

No Solution for θ \in R

sin (x) - 0.75 = 0

2 cos^{2} (x) + cos (x) - 6 = 0

sin (x) = sin (x + 1)

1 + cos (2 x) = sin (2 x)

cos (a) = \frac{6}{7.5}

What is the general solution for 3-2sin(θ)=-3+2sin(θ) ?
The general solution for 3-2sin(θ)=-3+2sin(θ) is No Solution for θ\in\mathbb{R}