What is the general solution for 2cos^2(x)-3=0 ?

The general solution for 2cos^2(x)-3=0 is No Solution for x\in\mathbb{R}

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2cos^2(x)-3=0

2 cos^{2} (x) - 3 = 0

No Solution for x \in R

Solution steps

2 cos^{2} (x) - 3 = 0

Solve by substitution

cos (x) = \frac{3}{2}, cos (x) = - \frac{3}{2}

cos (x) = \frac{3}{2} :

No Solution

cos (x) = - \frac{3}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

2 sin (x) + 3 tan (x) = 0

tan (t) = 2, 0 < t < \frac{π}{2}, cos (t)

\frac{cos ( x ) + sin ( x )}{sin ( x )} = \frac{1}{tan ( x )}

cos (2 x) - 3 sin (- x) - 2 = 0

sin (θ) = \frac{1}{4}, 0 < θ < \frac{π}{2}

What is the general solution for 2cos^2(x)-3=0 ?
The general solution for 2cos^2(x)-3=0 is No Solution for x\in\mathbb{R}