What is the general solution for 1+cot^2(x)=csc(x) ?

The general solution for 1+cot^2(x)=csc(x) is x= pi/2+2pin

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1+cot^2(x)=csc(x)

1 + cot^{2} (x) = csc (x)

x = \frac{π}{2} + 2 πn

Solution steps

1 + cot^{2} (x) = csc (x)

Subtract

csc (x)

from both sides

1 + cot^{2} (x) - csc (x) = 0

Rewrite using trig identities

- csc (x) + csc^{2} (x) = 0

Solve by substitution

csc (x) = 1, csc (x) = 0

csc (x) = 1 : x = \frac{π}{2} + 2 πn

csc (x) = 0 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

cos (θ) = \frac{7}{3 17}

sin (A) - 0.1 \cdot cos (A) = \frac{6.94}{9.8}

t, s = 2 arctan (t)

\frac{cos ( x )}{tan ( x )} = \frac{3}{2}

cos (2 x) + 5 cos (x) = 3

What is the general solution for 1+cot^2(x)=csc(x) ?
The general solution for 1+cot^2(x)=csc(x) is x= pi/2+2pin