What is the general solution for tan(x)-sqrt(3)=0,0<= x<= 2pi ?

The general solution for tan(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/3 ,x=(4pi)/3

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tan(x)-sqrt(3)=0,0<= x<= 2pi

tan (x) - 3 = 0, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{4 π}{3}

Degrees

x = 6 0^{\circ}, x = 24 0^{\circ}

Solution steps

tan (x) - 3 = 0, 0 \leq x \leq 2 π

Move

3

to the right side

tan (x) - 3 = 0

Add

3

to both sides

tan (x) - 3 + 3 = 0 + 3

Simplify

tan (x) = 3

tan (x) = 3

General solutions for

tan (x) = 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{3} + πn

x = \frac{π}{3} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{4 π}{3}

1 = tan (0 + c)

4 sin^{2} (x) = 3 - 4 sin (x)

tan (θ) = - \frac{2}{2}

\frac{sin ( 7 8 ^{\circ} )}{14} = \frac{sin ( a )}{6}

tan (x) = (- \frac{6}{5})

What is the general solution for tan(x)-sqrt(3)=0,0<= x<= 2pi ?
The general solution for tan(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/3 ,x=(4pi)/3