What is the general solution for 2cos(1/5 θ)=sqrt(3) ?

The general solution for 2cos(1/5 θ)=sqrt(3) is θ=(5pi)/6+10pin,θ=(55pi)/6+10pin

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2cos(1/5 θ)=sqrt(3)

2 cos (\frac{1}{5} θ) = 3

θ = \frac{5 π}{6} + 10 πn, θ = \frac{55 π}{6} + 10 πn

Solution steps

2 cos (\frac{1}{5} θ) = 3

Divide both sides by

2

cos (\frac{1}{5} θ) = \frac{3}{2}

General solutions for

cos (\frac{1}{5} θ) = \frac{3}{2}

\frac{1}{5} θ = \frac{π}{6} + 2 πn, \frac{1}{5} θ = \frac{11 π}{6} + 2 πn

Solve

\frac{1}{5} θ = \frac{π}{6} + 2 πn : θ = \frac{5 π}{6} + 10 πn

Solve

\frac{1}{5} θ = \frac{11 π}{6} + 2 πn : θ = \frac{55 π}{6} + 10 πn

θ = \frac{5 π}{6} + 10 πn, θ = \frac{55 π}{6} + 10 πn

sec (θ) = - \frac{7}{13}

tan (x) = - \infty

tan (2 x) = - tan (x) 2

2 sin^{2} (x) - 5 sin (x) - 12 = 0

\frac{1}{sin ( x )} = 5

What is the general solution for 2cos(1/5 θ)=sqrt(3) ?
The general solution for 2cos(1/5 θ)=sqrt(3) is θ=(5pi)/6+10pin,θ=(55pi)/6+10pin