What is the general solution for 2cos^2(t)-cos(t)-3=0 ?

The general solution for 2cos^2(t)-cos(t)-3=0 is t=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(t)-cos(t)-3=0

2 cos^{2} (t) - cos (t) - 3 = 0

t = π + 2 πn

Solution steps

2 cos^{2} (t) - cos (t) - 3 = 0

Solve by substitution

cos (t) = \frac{3}{2}, cos (t) = - 1

cos (t) = \frac{3}{2} :

No Solution

cos (t) = - 1 : t = π + 2 πn

Combine all the solutions

t = π + 2 πn

2 cos (4 θ + 20) = 0.8

2 - 2 cos^{2} (\frac{x}{2}) = sin^{2} (x)

sin (θ) = \frac{2}{2}, 0 \leq θ \leq 2 π

x, cos (x) = \frac{2}{3}

3 sin (x) + 2 = 1.5

What is the general solution for 2cos^2(t)-cos(t)-3=0 ?
The general solution for 2cos^2(t)-cos(t)-3=0 is t=pi+2pin