What is the general solution for 4cos(3x)=2 ?

The general solution for 4cos(3x)=2 is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3

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4cos(3x)=2

4 cos (3 x) = 2

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

Solution steps

4 cos (3 x) = 2

Divide both sides by

4

cos (3 x) = \frac{1}{2}

General solutions for

cos (3 x) = \frac{1}{2}

3 x = \frac{π}{3} + 2 πn, 3 x = \frac{5 π}{3} + 2 πn

Solve

3 x = \frac{π}{3} + 2 πn : x = \frac{π}{9} + \frac{2 πn}{3}

Solve

3 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

4 cos (2 x) = 4 cos^{2} (x) - 1

tan (8 b) = cot (10 b)

θ, cos (θ) = 0

sec^{2} (2 x) - 2 tan (2 x) = 0

x, d u = cos (4 x)

What is the general solution for 4cos(3x)=2 ?
The general solution for 4cos(3x)=2 is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3