What is the general solution for arccos(x)= 15/17 ?

The general solution for arccos(x)= 15/17 is x=cos(15/17)

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arccos(x)= 15/17

arccos (x) = \frac{15}{17}

x = cos (\frac{15}{17})

Solution steps

arccos (x) = \frac{15}{17}

Apply trig inverse properties

arccos (x) = \frac{15}{17}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{15}{17})

x = cos (\frac{15}{17})

4 tan^{2} (θ) - 9 = 0

sin (θ) = 7.19

3 = \frac{π}{3} sec^{2} (c)

\frac{sin ( 9 0 ^{\circ} )}{3.37} = \frac{sin ( x )}{0.7}

cos (x) = \frac{1 - cos ( x )}{2}

What is the general solution for arccos(x)= 15/17 ?
The general solution for arccos(x)= 15/17 is x=cos(15/17)