What is the general solution for sin(x)cos(x)=-(sqrt(2))/4 ?

The general solution for sin(x)cos(x)=-(sqrt(2))/4 is x=(5pi)/8+pin,x=(7pi)/8+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)cos(x)=-(sqrt(2))/4

sin (x) cos (x) = - \frac{2}{4}

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

sin (x) cos (x) = - \frac{2}{4}

Rewrite using trig identities

\frac{sin ( 2 x )}{2} = - \frac{2}{4}

Multiply both sides by

2

sin (2 x) = - \frac{2}{2}

General solutions for

sin (2 x) = - \frac{2}{2}

2 x = \frac{5 π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

sin (a) = 0.3

sin (x) = \frac{5}{13}, tan (x), \frac{π}{2} \leq x \leq π

sin (x) + cos^{2} (x) = \frac{5}{4}

2 cos^{2} (θ) - 5 cos (θ) - 3 = 0

15 sin (x) + 6 cos (x) - 3 = 0

What is the general solution for sin(x)cos(x)=-(sqrt(2))/4 ?
The general solution for sin(x)cos(x)=-(sqrt(2))/4 is x=(5pi)/8+pin,x=(7pi)/8+pin