What is the general solution for 24=32+8-2*sqrt(32*8)*cos(θ) ?

The general solution for 24=32+8-2*sqrt(32*8)*cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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24=32+8-2sqrt(328)*cos(θ)

24 = 32 + 8 - 2 \cdot 32 \cdot 8 \cdot cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

24 = 32 + 8 - 2 32 \cdot 8 cos (θ)

Switch sides

32 + 8 - 2 32 \cdot 8 cos (θ) = 24

2 32 \cdot 8 cos (θ) = 32 cos (θ)

32 + 8 - 32 cos (θ) = 24

Add the numbers:

32 + 8 = 40

- 32 cos (θ) + 40 = 24

Move

40

to the right side

- 32 cos (θ) = - 16

Divide both sides by

- 32

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

sin (4 5^{\circ} + a) cos (4 5^{\circ} + a) = \frac{2}{2}

tan (x) \cdot sin (x) = 5219

sin (z) = 2

2 \cdot sin^{2} (x) + sin (x) = 1

sin (x) = \frac{9}{10}

What is the general solution for 24=32+8-2*sqrt(32*8)*cos(θ) ?
The general solution for 24=32+8-2*sqrt(32*8)*cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin