What is the general solution for 10tan(B)+12=tan(B)+6 ?

The general solution for 10tan(B)+12=tan(B)+6 is B=-0.58800…+pin

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10tan(B)+12=tan(B)+6

10 tan (B) + 12 = tan (B) + 6

B = - 0.58800 \dots + πn

Solution steps

10 tan (B) + 12 = tan (B) + 6

Solve by substitution

tan (B) = - \frac{2}{3}

tan (B) = - \frac{2}{3} : B = arctan (- \frac{2}{3}) + πn

Combine all the solutions

B = arctan (- \frac{2}{3}) + πn

Show solutions in decimal form

B = - 0.58800 \dots + πn

cos (θ) = - \frac{5}{8}

\frac{368.02}{sin ( 6 6 ^{\circ} - x )} = \frac{290}{sin ( 3 8 ^{\circ} )}

cos^{2} (x) sec (x) = 1

tan (x) = \frac{9.3}{7.5}

sin (α) + cos (α) = 1

What is the general solution for 10tan(B)+12=tan(B)+6 ?
The general solution for 10tan(B)+12=tan(B)+6 is B=-0.58800…+pin