What is the general solution for 4tan(θ)=5-tan(θ) ?

The general solution for 4tan(θ)=5-tan(θ) is θ= pi/4+pin

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4tan(θ)=5-tan(θ)

4 tan (θ) = 5 - tan (θ)

θ = \frac{π}{4} + πn

Solution steps

4 tan (θ) = 5 - tan (θ)

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

2 sec (x) = 1

sin (2 x) = cos (x), 0 \leq < 2 π

x, y^{1} = sin (x)

tan (θ) = \frac{15}{6}

- cos (2 x) = cos^{2} (x) - sin^{2} (x)

What is the general solution for 4tan(θ)=5-tan(θ) ?
The general solution for 4tan(θ)=5-tan(θ) is θ= pi/4+pin