What is the general solution for sin^2(x)=-(1/2) ?

The general solution for sin^2(x)=-(1/2) is No Solution for x\in\mathbb{R}

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sin^2(x)=-(1/2)

sin^{2} (x) = - (\frac{1}{2})

No Solution for x \in R

Solution steps

sin^{2} (x) = - (\frac{1}{2})

Solve by substitution

sin (x) = i \frac{1}{2}, sin (x) = - i \frac{1}{2}

sin (x) = i \frac{1}{2} :

No Solution

sin (x) = - i \frac{1}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

α, sin^{2} (3 α) = 0.56

(sin (x) - cos (x))^{2} = 1^{2}

tan (\frac{π}{2} - x) + 2 tan (\frac{π}{2} + x) = 1

\frac{11.0994}{cos ( x )} = \frac{3.5355}{sin ( x )}

(\frac{sec ( x )}{cos ( x )})^{2} = tan^{2} (x)

What is the general solution for sin^2(x)=-(1/2) ?
The general solution for sin^2(x)=-(1/2) is No Solution for x\in\mathbb{R}