What is the general solution for cos^2(x)+sin^2(x)=sin(x)+1/2 ?

The general solution for cos^2(x)+sin^2(x)=sin(x)+1/2 is x= pi/6+2pin,x=(5pi)/6+2pin

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cos^2(x)+sin^2(x)=sin(x)+1/2

cos^{2} (x) + sin^{2} (x) = sin (x) + \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

cos^{2} (x) + sin^{2} (x) = sin (x) + \frac{1}{2}

Rewrite using trig identities

1 = sin (x) + \frac{1}{2}

Switch sides

sin (x) + \frac{1}{2} = 1

Move

\frac{1}{2}

to the right side

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (A) = 0.53

tan (a) = 3, cos (a)

2 sin (2 x) = cos (2 x)

sin (2 θ) = 3

1 2^{2} = 1 5^{2} + 2 0^{2} - 2 (15) (20) (cos (a))

What is the general solution for cos^2(x)+sin^2(x)=sin(x)+1/2 ?
The general solution for cos^2(x)+sin^2(x)=sin(x)+1/2 is x= pi/6+2pin,x=(5pi)/6+2pin