en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7=10sin(40(0-h))+17

Solution

7 = 10 sin (40 (0 - h)) + 17

Solution

h = - \frac{3 π}{80} - \frac{πn}{20}

+1

Solution steps

7 = 10 sin (40 (0 - h)) + 17

Switch sides

10 sin (40 (0 - h)) + 17 = 7

Move

17

to the right side

10 sin (40 (0 - h)) = - 10

Divide both sides by

10

sin (40 (0 - h)) = - 1

General solutions for

sin (40 (0 - h)) = - 1

40 (0 - h) = \frac{3 π}{2} + 2 πn

Solve

40 (0 - h) = \frac{3 π}{2} + 2 πn : h = - \frac{3 π}{80} - \frac{πn}{20}

h = - \frac{3 π}{80} - \frac{πn}{20}

Popular Examples

sin(2x)=cos(x),0<= x<2pi

sin (2 x) = cos (x), 0 \leq x < 2 π

sec (x) = - \frac{5}{3}

(sin(x))/(1+cos(x))=sin(x/2)

\frac{sin ( x )}{1 + cos ( x )} = sin (\frac{x}{2})

sqrt(2)*cos(x/2)-cos(x)=1

2 \cdot cos (\frac{x}{2}) - cos (x) = 1

2sin(θ)cos(θ)+2sin(θ)-2cos(θ)sin(θ)=0

2 sin (θ) cos (θ) + 2 sin (θ) - 2 cos (θ) sin (θ) = 0

Frequently Asked Questions (FAQ)

What is the general solution for 7=10sin(40(0-h))+17 ?
The general solution for 7=10sin(40(0-h))+17 is h=-(3pi)/(80)-(pin)/(20)