What is the general solution for 28cos^2(θ)=7 ?

The general solution for 28cos^2(θ)=7 is θ= pi/3+2pin,θ=(5pi)/3+2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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28cos^2(θ)=7

28 cos^{2} (θ) = 7

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

28 cos^{2} (θ) = 7

Solve by substitution

cos (θ) = \frac{1}{2}, cos (θ) = - \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

3 - cos (6 x) \cdot 6 = 0

sin (x) - cos (x) = 1, 0 \leq x \leq 36 0^{\circ}

cos (x) = 0, 6

cos (x) = 0, 5

25 cos^{2} (x) = 9

What is the general solution for 28cos^2(θ)=7 ?
The general solution for 28cos^2(θ)=7 is θ= pi/3+2pin,θ=(5pi)/3+2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin