What is the general solution for tan^2(x)-sin(x)tan^2(x)=0 ?

The general solution for tan^2(x)-sin(x)tan^2(x)=0 is x=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan^2(x)-sin(x)tan^2(x)=0

tan^{2} (x) - sin (x) tan^{2} (x) = 0

x = πn

Solution steps

tan^{2} (x) - sin (x) tan^{2} (x) = 0

Factor

tan^{2} (x) - sin (x) tan^{2} (x) : - tan^{2} (x) (sin (x) - 1)

- tan^{2} (x) (sin (x) - 1) = 0

Solving each part separately

tan^{2} (x) = 0 or sin (x) - 1 = 0

tan^{2} (x) = 0 : x = πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = πn

- 1 - tan (x) = sec (x), 0 \leq x < 2 π

cosh (z) + 1 = 0

tan (x) = 11, sin (x)

4 sin (x) = 2.54648

y, \frac{3}{2} = sin (arcsin (0) + y)

What is the general solution for tan^2(x)-sin(x)tan^2(x)=0 ?
The general solution for tan^2(x)-sin(x)tan^2(x)=0 is x=pin