What is the general solution for tan^2(x)+1=a^2 ?

The general solution for tan^2(x)+1=a^2 is x=arctan(sqrt(a^2-1))+pin,x=arctan(-sqrt(a^2-1))+pin

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tan^2(x)+1=a^2

tan^{2} (x) + 1 = a^{2}

x = arctan (a^{2} - 1) + πn, x = arctan (- a^{2} - 1) + πn

Solution steps

tan^{2} (x) + 1 = a^{2}

Solve by substitution

tan (x) = a^{2} - 1, tan (x) = - a^{2} - 1

tan (x) = a^{2} - 1 : x = arctan (a^{2} - 1) + πn

tan (x) = - a^{2} - 1 : x = arctan (- a^{2} - 1) + πn

Combine all the solutions

x = arctan (a^{2} - 1) + πn, x = arctan (- a^{2} - 1) + πn

2 = 2 cos (t)

50 sin (4 5^{\circ}) = 600 sin (θ)

a, tan (a \cdot x^{0.5}) = - x^{0.5}

sin (x) = 35, csc (x)

2 + 2 cos (x) = \frac{2}{1 + cos ( x )}

What is the general solution for tan^2(x)+1=a^2 ?
The general solution for tan^2(x)+1=a^2 is x=arctan(sqrt(a^2-1))+pin,x=arctan(-sqrt(a^2-1))+pin