What is the general solution for cos^2(θ)+0.339cos(θ)-1=0 ?

The general solution for cos^2(θ)+0.339cos(θ)-1=0 is θ=0.56467…+2pin,θ=2pi-0.56467…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^2(θ)+0.339cos(θ)-1=0

cos^{2} (θ) + 0.339 cos (θ) - 1 = 0

θ = 0.56467 \dots + 2 πn, θ = 2 π - 0.56467 \dots + 2 πn

Solution steps

cos^{2} (θ) + 0.339 cos (θ) - 1 = 0

Solve by substitution

cos (θ) = \frac{- 339 + 4114921}{2000}, cos (θ) = \frac{- 339 - 4114921}{2000}

cos (θ) = \frac{- 339 + 4114921}{2000} : θ = arccos (\frac{- 339 + 4114921}{2000}) + 2 πn, θ = 2 π - arccos (\frac{- 339 + 4114921}{2000}) + 2 πn

cos (θ) = \frac{- 339 - 4114921}{2000} :

No Solution

Combine all the solutions

θ = arccos (\frac{- 339 + 4114921}{2000}) + 2 πn, θ = 2 π - arccos (\frac{- 339 + 4114921}{2000}) + 2 πn

Show solutions in decimal form

θ = 0.56467 \dots + 2 πn, θ = 2 π - 0.56467 \dots + 2 πn

sin (x) = \frac{2 2}{3}

arctan (θ) = 7 \cdot \frac{540}{15}

k sin (x) - c = 0

cos (x) = sin (x - \frac{π}{2})

5 cos (x) + 2 = 0, 0 \leq x \leq 2 π

What is the general solution for cos^2(θ)+0.339cos(θ)-1=0 ?
The general solution for cos^2(θ)+0.339cos(θ)-1=0 is θ=0.56467…+2pin,θ=2pi-0.56467…+2pin