What is the general solution for 2sin(2x+pi/3)=1 ?

The general solution for 2sin(2x+pi/3)=1 is x=pin-pi/(12),x=pin+pi/4

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2sin(2x+pi/3)=1

2 sin (2 x + \frac{π}{3}) = 1

x = πn - \frac{π}{12}, x = πn + \frac{π}{4}

Solution steps

2 sin (2 x + \frac{π}{3}) = 1

Divide both sides by

2

sin (2 x + \frac{π}{3}) = \frac{1}{2}

General solutions for

sin (2 x + \frac{π}{3}) = \frac{1}{2}

2 x + \frac{π}{3} = \frac{π}{6} + 2 πn, 2 x + \frac{π}{3} = \frac{5 π}{6} + 2 πn

Solve

2 x + \frac{π}{3} = \frac{π}{6} + 2 πn : x = πn - \frac{π}{12}

Solve

2 x + \frac{π}{3} = \frac{5 π}{6} + 2 πn : x = πn + \frac{π}{4}

x = πn - \frac{π}{12}, x = πn + \frac{π}{4}

sec (x) = 2, cos (x)

- cosh (sech (x)) (sech (x) tanh (x)) = 0

\frac{sin ( 9 7 ^{\circ} )}{14} = \frac{sin ( b )}{10}

tan (x) = \frac{5 + cos ( x )}{6 sin ( x ) cos ( x )}

cos (x - 1) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

What is the general solution for 2sin(2x+pi/3)=1 ?
The general solution for 2sin(2x+pi/3)=1 is x=pin-pi/(12),x=pin+pi/4