What is the general solution for sqrt(9cos(2θ))=0 ?

The general solution for sqrt(9cos(2θ))=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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sqrt(9cos(2θ))=0

9 cos (2 θ) = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

9 cos (2 θ) = 0

Square both sides:

9 cos (2 θ) = 0

9 cos (2 θ) = 0

Solve

9 cos (2 θ) = 0 : cos (2 θ) = 0

cos (2 θ) = 0

Verify Solutions:

cos (2 θ) = 0

True

The solution is

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

cos (A) = \frac{2}{3}

2 sin (θ) = 3 (1 - cos (θ))

4 sin^{2} (x) tan (x) - 4 sin^{2} (x) - 3 tan (x) + 3 = 0

cos (t) = - 0, 5

sinh (x) = sinh (- x)

What is the general solution for sqrt(9cos(2θ))=0 ?
The general solution for sqrt(9cos(2θ))=0 is θ= pi/4+pin,θ=(3pi)/4+pin