What is the general solution for -4pi^2sin(2pix)=0 ?

The general solution for -4pi^2sin(2pix)=0 is x=n,x= 1/2+n

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-4pi^2sin(2pix)=0

- 4 π^{2} sin (2 π x) = 0

x = n, x = \frac{1}{2} + n

Solution steps

- 4 π^{2} sin (2 π x) = 0

Divide both sides by

- 4 π^{2}

sin (2 π x) = 0

General solutions for

sin (2 π x) = 0

2 π x = 0 + 2 πn, 2 π x = π + 2 πn

Solve

2 π x = 0 + 2 πn : x = n

Solve

2 π x = π + 2 πn : x = \frac{1}{2} + n

x = n, x = \frac{1}{2} + n

- 9 sin (y) = 0

6 + 4 cos (2 x) = 2 - 4 cos (x)

x, cos (x) = y

tan (θ) = \frac{48}{90}

cos (θ) - 1 = 2 cos^{2} (θ) - 1

What is the general solution for -4pi^2sin(2pix)=0 ?
The general solution for -4pi^2sin(2pix)=0 is x=n,x= 1/2+n