What is the general solution for 100=50sqrt(40)cos(θ) ?

The general solution for 100=50sqrt(40)cos(θ) is θ=1.24904…+2pin,θ=2pi-1.24904…+2pin

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100=50sqrt(40)cos(θ)

100 = 5040 cos (θ)

θ = 1.24904 \dots + 2 πn, θ = 2 π - 1.24904 \dots + 2 πn

Solution steps

100 = 5040 cos (θ)

Switch sides

5040 cos (θ) = 100

Simplify

5040 : 10010

10010 cos (θ) = 100

Divide both sides by

10010

cos (θ) = \frac{10}{10}

Apply trig inverse properties

θ = arccos (\frac{10}{10}) + 2 πn, θ = 2 π - arccos (\frac{10}{10}) + 2 πn

Show solutions in decimal form

θ = 1.24904 \dots + 2 πn, θ = 2 π - 1.24904 \dots + 2 πn

cos (3 x) = \frac{2}{3}

cos (x) (csc (x) + 2) = 0

arctan (θ) = \frac{π}{4}

4 cos^{3} (x) - 7 cos (x) - 3 = 0

\frac{sin ( θ )}{1.3} = \frac{sin ( 12 5 ^{\circ} )}{2.8519}

What is the general solution for 100=50sqrt(40)cos(θ) ?
The general solution for 100=50sqrt(40)cos(θ) is θ=1.24904…+2pin,θ=2pi-1.24904…+2pin