What is the general solution for 2+cos(θ)=5cos(θ) ?

The general solution for 2+cos(θ)=5cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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2+cos(θ)=5cos(θ)

2 + cos (θ) = 5 cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

2 + cos (θ) = 5 cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

11 = 12 + 3.1 cos (\frac{2 π}{365} t)

θ, 6 sin^{2} (θ) - 3 = 0

sin (x) = - \frac{7}{8}

sin (x) = 0.942

4 cos^{2} (x) = 5 + 4 sin (x), (0, 2 π)

What is the general solution for 2+cos(θ)=5cos(θ) ?
The general solution for 2+cos(θ)=5cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin