What is the general solution for 4-4sin(θ)=2 ?

The general solution for 4-4sin(θ)=2 is θ= pi/6+2pin,θ=(5pi)/6+2pin

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4-4sin(θ)=2

4 - 4 sin (θ) = 2

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

4 - 4 sin (θ) = 2

Move

4

to the right side

- 4 sin (θ) = - 2

Divide both sides by

- 4

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

1 - 2 cos (x) = sin^{2} (x)

cos (x) = \frac{84}{98}

cos (\frac{3 θ}{2}) = \frac{1}{2}

0 = 5 + 4 cos (x)

35708 = 35795 cos (x)

What is the general solution for 4-4sin(θ)=2 ?
The general solution for 4-4sin(θ)=2 is θ= pi/6+2pin,θ=(5pi)/6+2pin