What is the general solution for -2cos(2θ)=1 ?

The general solution for -2cos(2θ)=1 is θ= pi/3+pin,θ=(2pi)/3+pin

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-2cos(2θ)=1

- 2 cos (2 θ) = 1

θ = \frac{π}{3} + πn, θ = \frac{2 π}{3} + πn

Solution steps

- 2 cos (2 θ) = 1

Divide both sides by

- 2

cos (2 θ) = - \frac{1}{2}

General solutions for

cos (2 θ) = - \frac{1}{2}

2 θ = \frac{2 π}{3} + 2 πn, 2 θ = \frac{4 π}{3} + 2 πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

Solve

2 θ = \frac{4 π}{3} + 2 πn : θ = \frac{2 π}{3} + πn

θ = \frac{π}{3} + πn, θ = \frac{2 π}{3} + πn

tan (5 x) \cdot cot (x + 4 0^{\circ}) = 1

sin (θ) = 0.7043

3 cosh (2 x) = 5

θ, 4 sin (θ) + 3 cos (θ) = 2

tan (x) n = 3

What is the general solution for -2cos(2θ)=1 ?
The general solution for -2cos(2θ)=1 is θ= pi/3+pin,θ=(2pi)/3+pin