What is the general solution for tanh(x+1)+1=2 ?

The general solution for tanh(x+1)+1=2 is No Solution for x\in\mathbb{R}

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tanh(x+1)+1=2

tanh (x + 1) + 1 = 2

No Solution for x \in R

Solution steps

tanh (x + 1) + 1 = 2

Rewrite using trig identities

\frac{e ^{x + 1} - e ^{- (x + 1)}}{e ^{x + 1} + e ^{- (x + 1)}} + 1 = 2

\frac{e ^{x + 1} - e ^{- (x + 1)}}{e ^{x + 1} + e ^{- (x + 1)}} + 1 = 2 :

No Solution for

x \in R

No Solution for x \in R

sin (2 θ) = 0.9076

7 sin (B) + 3 = sin (B) + 2

4 cos (x) = 3

cos (x + \frac{1}{6} π) cos (x - \frac{1}{6} π) = cos (2 x)

tan (\frac{a}{2}) = \frac{1}{2}

What is the general solution for tanh(x+1)+1=2 ?
The general solution for tanh(x+1)+1=2 is No Solution for x\in\mathbb{R}