What is the general solution for 2cos^2(x)+sin^2(x)=1 ?

The general solution for 2cos^2(x)+sin^2(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin

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2cos^2(x)+sin^2(x)=1

2 cos^{2} (x) + sin^{2} (x) = 1

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

2 cos^{2} (x) + sin^{2} (x) = 1

Subtract

1

from both sides

2 cos^{2} (x) + sin^{2} (x) - 1 = 0

Rewrite using trig identities

cos^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

3 \cdot tan^{2} (x) = 1

2 \cdot 3 sin (v) + 2 cos (v) = 22

2 csc^{3} (x) + 21 csc^{2} (x) + 55 csc (x) + 42 = 0

cos^{2} (\frac{x}{3}) - sin^{2} (\frac{x}{3}) = - \frac{1}{2}

sin (x) = 0.014

What is the general solution for 2cos^2(x)+sin^2(x)=1 ?
The general solution for 2cos^2(x)+sin^2(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin