What is the general solution for solvefor x,sin^2(x)=(5m-5)/2 ?

The general solution for solvefor x,sin^2(x)=(5m-5)/2 is

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solvefor x,sin^2(x)=(5m-5)/2

solve for

x, sin^{2} (x) = \frac{5 m - 5}{2}

x = arcsin (\frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (- \frac{5 m - 5}{2}) + 2 πn, x = arcsin (- \frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (\frac{5 m - 5}{2}) + 2 πn

Solution steps

sin^{2} (x) = \frac{5 m - 5}{2}

Solve by substitution

sin (x) = \frac{5 m - 5}{2}, sin (x) = - \frac{5 m - 5}{2}

sin (x) = \frac{5 m - 5}{2} : x = arcsin (\frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (- \frac{5 m - 5}{2}) + 2 πn

sin (x) = - \frac{5 m - 5}{2} : x = arcsin (- \frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (\frac{5 m - 5}{2}) + 2 πn

Combine all the solutions

x = arcsin (\frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (- \frac{5 m - 5}{2}) + 2 πn, x = arcsin (- \frac{5 m - 5}{2}) + 2 πn, x = π + arcsin (\frac{5 m - 5}{2}) + 2 πn

csc (θ) = - 1.343

csc (θ) = - \frac{3}{2}, π < θ < \frac{3 π}{2}, sin (θ)

\frac{2 - 3 sin ( θ )}{2} = - 3 sin (θ)

sin (2 x) = \frac{- 3}{2}

x, arctan (x) = \frac{π y}{4}

What is the general solution for solvefor x,sin^2(x)=(5m-5)/2 ?
The general solution for solvefor x,sin^2(x)=(5m-5)/2 is