What is the general solution for 2sin(x)-sin(x)cos(x)=0 ?

The general solution for 2sin(x)-sin(x)cos(x)=0 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(x)-sin(x)cos(x)=0

2 sin (x) - sin (x) cos (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin (x) - sin (x) cos (x) = 0

Factor

2 sin (x) - sin (x) cos (x) : - sin (x) (cos (x) - 2)

- sin (x) (cos (x) - 2) = 0

Solving each part separately

sin (x) = 0 or cos (x) - 2 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

cos (x) - 2 = 0 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

3 sin (x) - 2 cos (x) = 7

cos (x) = 0.6345

cos (t) = \frac{40}{41}

5 tan (x) = 12

cos^{2} (a) + cos (a) = 0

What is the general solution for 2sin(x)-sin(x)cos(x)=0 ?
The general solution for 2sin(x)-sin(x)cos(x)=0 is x=2pin,x=pi+2pin