What is the general solution for -2cos(θ/2)=0 ?

The general solution for -2cos(θ/2)=0 is θ=pi+4pin,θ=3pi+4pin

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-2cos(θ/2)=0

- 2 cos (\frac{θ}{2}) = 0

θ = π + 4 πn, θ = 3 π + 4 πn

Solution steps

- 2 cos (\frac{θ}{2}) = 0

Divide both sides by

- 2

cos (\frac{θ}{2}) = 0

General solutions for

cos (\frac{θ}{2}) = 0

\frac{θ}{2} = \frac{π}{2} + 2 πn, \frac{θ}{2} = \frac{3 π}{2} + 2 πn

Solve

\frac{θ}{2} = \frac{π}{2} + 2 πn : θ = π + 4 πn

Solve

\frac{θ}{2} = \frac{3 π}{2} + 2 πn : θ = 3 π + 4 πn

θ = π + 4 πn, θ = 3 π + 4 πn

cos (x) = - \frac{3}{4}, tan (x) i s

cos (θ) = \frac{- 1}{3}

cos (2 x) + sin (x) = 4 sin^{2} (x)

- 2 sin^{2} (x) - 5 sin (x) = - 3

b, a = cos (- 1 (\frac{a}{a ^{2} + b ^{2}}))

What is the general solution for -2cos(θ/2)=0 ?
The general solution for -2cos(θ/2)=0 is θ=pi+4pin,θ=3pi+4pin