What is the general solution for solvefor θ,r=2sin(θ) ?

The general solution for solvefor θ,r=2sin(θ) is θ=arcsin(r/2)+2pin,θ=pi+arcsin(-r/2)+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor θ,r=2sin(θ)

solve for

θ, r = 2 sin (θ)

θ = arcsin (\frac{r}{2}) + 2 πn, θ = π + arcsin (- \frac{r}{2}) + 2 πn

Solution steps

r = 2 sin (θ)

Switch sides

2 sin (θ) = r

Divide both sides by

2

sin (θ) = \frac{r}{2}

Apply trig inverse properties

θ = arcsin (\frac{r}{2}) + 2 πn, θ = π + arcsin (- \frac{r}{2}) + 2 πn

csc (3 θ) = - 1

cos (x) = 0.1234

tan (2 x) = + \frac{9}{40}

x, y = cos (6 x)

12 cos^{2} (x) - 6 sin (x) - 6 = 0 [360]

What is the general solution for solvefor θ,r=2sin(θ) ?
The general solution for solvefor θ,r=2sin(θ) is θ=arcsin(r/2)+2pin,θ=pi+arcsin(-r/2)+2pin