What is the general solution for cos(2x)-7cos(x)+6=0 ?

The general solution for cos(2x)-7cos(x)+6=0 is x=2pin

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cos(2x)-7cos(x)+6=0

cos (2 x) - 7 cos (x) + 6 = 0

x = 2 πn

Solution steps

cos (2 x) - 7 cos (x) + 6 = 0

Rewrite using trig identities

5 + 2 cos^{2} (x) - 7 cos (x) = 0

Solve by substitution

cos (x) = \frac{5}{2}, cos (x) = 1

cos (x) = \frac{5}{2} :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

csc^{2} (x) = 2 + csc (x)

tan (θ) = \frac{5.4}{1.1}

6 cos (2 θ) + 3 = 0

(sin (θ) + cos^{2} (θ))^{2} = 2 sin (θ)

\frac{2}{3} = sin (2 θ)

What is the general solution for cos(2x)-7cos(x)+6=0 ?
The general solution for cos(2x)-7cos(x)+6=0 is x=2pin