What is the general solution for solvefor x,arcsin(x)=arccos(y) ?

The general solution for solvefor x,arcsin(x)=arccos(y) is x=sin(arccos(y))

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solvefor x,arcsin(x)=arccos(y)

solve for

x, arcsin (x) = arccos (y)

x = sin (arccos (y))

Solution steps

arcsin (x) = arccos (y)

Apply trig inverse properties

arcsin (x) = arccos (y)

arcsin (x) = a \Rightarrow x = sin (a)

x = sin (arccos (y))

x = sin (arccos (y))

sin (x) = \frac{4.9}{7.5}

\frac{1}{cos ( x )} + sec^{2} (x) - 1 - cos (x) = 0

(sin (x) + cos (x))^{2} = 0

(sin (x) + cos (x))^{2} = 2

tan (θ) = \frac{3}{3}, 18 0^{\circ} \leq θ \leq 36 0^{\circ}

What is the general solution for solvefor x,arcsin(x)=arccos(y) ?
The general solution for solvefor x,arcsin(x)=arccos(y) is x=sin(arccos(y))