What is the general solution for cos(θ)=-(sqrt(7))/5 ?

The general solution for cos(θ)=-(sqrt(7))/5 is θ=2.12839…+2pin,θ=-2.12839…+2pin

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cos(θ)=-(sqrt(7))/5

cos (θ) = - \frac{7}{5}

θ = 2.12839 \dots + 2 πn, θ = - 2.12839 \dots + 2 πn

Solution steps

cos (θ) = - \frac{7}{5}

Apply trig inverse properties

θ = arccos (- \frac{7}{5}) + 2 πn, θ = - arccos (- \frac{7}{5}) + 2 πn

Show solutions in decimal form

θ = 2.12839 \dots + 2 πn, θ = - 2.12839 \dots + 2 πn

sin (π + x) = sin (x)

cos (x) = - \frac{2}{π}

23 cos (z) + 2 sin (z) = 0

\frac{cos ( x ) + cos ( 3 x )}{cos ^{2} ( x ) - sin ^{2} ( x )} = 0

sin (x) = 2 cos^{2} (x) - 1

What is the general solution for cos(θ)=-(sqrt(7))/5 ?
The general solution for cos(θ)=-(sqrt(7))/5 is θ=2.12839…+2pin,θ=-2.12839…+2pin