What is the general solution for 1+cos(θ)=1+sin(θ) ?

The general solution for 1+cos(θ)=1+sin(θ) is θ= pi/4+pin

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1+cos(θ)=1+sin(θ)

1 + cos (θ) = 1 + sin (θ)

θ = \frac{π}{4} + πn

Solution steps

1 + cos (θ) = 1 + sin (θ)

Subtract

1 + sin (θ)

from both sides

cos (θ) - sin (θ) = 0

Rewrite using trig identities

1 - tan (θ) = 0

Move

1

to the right side

- tan (θ) = - 1

Divide both sides by

- 1

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

500 = 538 cos (x - 1 0^{\circ})

0 = sec^{2} (x) e^{t a n (x)} (2 tan (x) + sec^{2} (x))

tan (x) = 3, - 18 0^{\circ} < x < 18 0^{\circ}

cot^{2} (t) csc (t) = sin (t)

\frac{6}{12} = cos (θ)

What is the general solution for 1+cos(θ)=1+sin(θ) ?
The general solution for 1+cos(θ)=1+sin(θ) is θ= pi/4+pin