What is the general solution for ((sin^2(x)))/((1-cos(x)))=1.23 ?

The general solution for ((sin^2(x)))/((1-cos(x)))=1.23 is x=1.33871…+2pin,x=2pi-1.33871…+2pin

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((sin^2(x)))/((1-cos(x)))=1.23

\frac{( sin ^{2} ( x ) )}{( 1 - cos ( x ) )} = 1.23

x = 1.33871 \dots + 2 πn, x = 2 π - 1.33871 \dots + 2 πn

Solution steps

\frac{( sin ^{2} ( x ) )}{( 1 - cos ( x ) )} = 1.23

Subtract

1.23

from both sides

\frac{sin ^{2} ( x )}{1 - cos ( x )} - 1.23 = 0

Rewrite using trig identities

- 0.23 + cos (x) = 0

Move

0.23

to the right side

cos (x) = 0.23

Apply trig inverse properties

x = arccos (0.23) + 2 πn, x = 2 π - arccos (0.23) + 2 πn

Show solutions in decimal form

x = 1.33871 \dots + 2 πn, x = 2 π - 1.33871 \dots + 2 πn

- 1 = tan (2 (0)^{3} + C)

sin (x) = \frac{1}{2}, 0 < x < \frac{π}{2}

sin (2 x) = cos (8 x)

8 = sin (x)

arctan (4 x) + arctan (6 x) = - \frac{π}{2}

What is the general solution for ((sin^2(x)))/((1-cos(x)))=1.23 ?
The general solution for ((sin^2(x)))/((1-cos(x)))=1.23 is x=1.33871…+2pin,x=2pi-1.33871…+2pin