What is the general solution for -10cos(θ)=-2-6cos(θ) ?

The general solution for -10cos(θ)=-2-6cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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-10cos(θ)=-2-6cos(θ)

- 10 cos (θ) = - 2 - 6 cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

- 10 cos (θ) = - 2 - 6 cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

sin (a) = (\frac{( 8 )}{( 153 )})

2 csc^{2} (x) - 1 = 0

- sec (θ) cot (θ) - sec (θ) = - 2 sec (θ)

sec^{2} (a) = \frac{4}{3}

sin (5 x - 27) = cos (6 x + 13.6)

What is the general solution for -10cos(θ)=-2-6cos(θ) ?
The general solution for -10cos(θ)=-2-6cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin