What is the general solution for 2cos^2(t)+7cos(t)+5=0 ?

The general solution for 2cos^2(t)+7cos(t)+5=0 is t=pi+2pin

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2cos^2(t)+7cos(t)+5=0

2 cos^{2} (t) + 7 cos (t) + 5 = 0

t = π + 2 πn

Solution steps

2 cos^{2} (t) + 7 cos (t) + 5 = 0

Solve by substitution

cos (t) = - 1, cos (t) = - \frac{5}{2}

cos (t) = - 1 : t = π + 2 πn

cos (t) = - \frac{5}{2} :

No Solution

Combine all the solutions

t = π + 2 πn

cos (x) = \frac{35}{45}

\frac{π}{6} = cos (2 t)

x, 3 tan (2 x) = 1

y, x = 5 \cdot sin (y)

12 cos^{2} (x) - cos (x) - 1 = 0

What is the general solution for 2cos^2(t)+7cos(t)+5=0 ?
The general solution for 2cos^2(t)+7cos(t)+5=0 is t=pi+2pin