What is the general solution for sin(θ)=(3sqrt(2-\sqrt{3)})/(40) ?

The general solution for sin(θ)=(3sqrt(2-\sqrt{3)})/(40) is θ=0.03883…+2pin,θ=pi-0.03883…+2pin

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sin(θ)=(3sqrt(2-\sqrt{3)})/(40)

sin (θ) = \frac{3 2 - 3}{40}

θ = 0.03883 \dots + 2 πn, θ = π - 0.03883 \dots + 2 πn

Solution steps

sin (θ) = \frac{3 2 - 3}{40}

Apply trig inverse properties

θ = arcsin (\frac{3 2 - 3}{40}) + 2 πn, θ = π - arcsin (\frac{3 2 - 3}{40}) + 2 πn

Show solutions in decimal form

θ = 0.03883 \dots + 2 πn, θ = π - 0.03883 \dots + 2 πn

cos^{2} (x) + 5 cos (x) - 3 = 0

2 sin^{2} (x) - sin (x) cos (x) - cos^{2} (x) = 0

cos^{4} (a) + cos^{2} (a) + sin^{2} (a) + sin^{2} (a) = 1

22 sin (x) + sec (x) = 0

cos (θ) = \frac{- 2}{( 30 + ( 7 ) )}

What is the general solution for sin(θ)=(3sqrt(2-\sqrt{3)})/(40) ?
The general solution for sin(θ)=(3sqrt(2-\sqrt{3)})/(40) is θ=0.03883…+2pin,θ=pi-0.03883…+2pin