What is the general solution for 2sin(x)=sqrt(3),0<= x<= 2pi ?

The general solution for 2sin(x)=sqrt(3),0<= x<= 2pi is x= pi/3 ,x=(2pi)/3

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2sin(x)=sqrt(3),0<= x<= 2pi

2 sin (x) = 3, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

Solution steps

2 sin (x) = 3, 0 \leq x \leq 2 π

Divide both sides by

2

sin (x) = \frac{3}{2}

General solutions for

sin (x) = \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

x, z = arcsin (x + y)

150 cos (x - 8) = 0

8 sin^{2} (x) - 6 sin (x) + 1 = 0

sin (5 x) - cos (3 0^{\circ}) = 0

2 cos^{2} (t) + 2 cos (2 t) = 0

What is the general solution for 2sin(x)=sqrt(3),0<= x<= 2pi ?
The general solution for 2sin(x)=sqrt(3),0<= x<= 2pi is x= pi/3 ,x=(2pi)/3