What is the general solution for 5+cos^2(θ)-6cos(θ)=0 ?

The general solution for 5+cos^2(θ)-6cos(θ)=0 is θ=2pin

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5+cos^2(θ)-6cos(θ)=0

5 + cos^{2} (θ) - 6 cos (θ) = 0

θ = 2 πn

Solution steps

5 + cos^{2} (θ) - 6 cos (θ) = 0

Solve by substitution

cos (θ) = 5, cos (θ) = 1

cos (θ) = 5 :

No Solution

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = 2 πn

tan (2 c) = - tan (x)

2 sin (x) cos (x) = sin^{2} (x)

sin (θ) - 0.1 cos (θ) = \frac{8.87}{9.8}

2 sin (x) = \frac{sin ( x )}{cos ( x )}

6 sin^{2} (x) = 5 + cos (x), 18 0^{\circ} \leq x \leq 54 0^{\circ}

What is the general solution for 5+cos^2(θ)-6cos(θ)=0 ?
The general solution for 5+cos^2(θ)-6cos(θ)=0 is θ=2pin