What is the general solution for 2cot(2x)+2=0 ?

The general solution for 2cot(2x)+2=0 is x=(3pi)/8+(pin)/2

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2cot(2x)+2=0

2 cot (2 x) + 2 = 0

x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

2 cot (2 x) + 2 = 0

Move

2

to the right side

2 cot (2 x) = - 2

Divide both sides by

2

cot (2 x) = - 1

General solutions for

cot (2 x) = - 1

2 x = \frac{3 π}{4} + πn

Solve

2 x = \frac{3 π}{4} + πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{3 π}{8} + \frac{πn}{2}

sin (x - π) = \frac{- 2}{2}

sec^{2} (θ) tan (θ) = 2 tan (θ), 0^{\circ} \leq θ \leq 36 0^{\circ}

arccos (x) = 18 0^{\circ}

sin (a) = \frac{29.7}{54.5}

1.0003 sin (3 0^{\circ}) = 1.46 sin (x)

What is the general solution for 2cot(2x)+2=0 ?
The general solution for 2cot(2x)+2=0 is x=(3pi)/8+(pin)/2