What is the general solution for cot^2(x)+csc(x)+1=0 ?

The general solution for cot^2(x)+csc(x)+1=0 is x=(3pi)/2+2pin

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cot^2(x)+csc(x)+1=0

cot^{2} (x) + csc (x) + 1 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

cot^{2} (x) + csc (x) + 1 = 0

Rewrite using trig identities

csc (x) + csc^{2} (x) = 0

Solve by substitution

csc (x) = 0, csc (x) = - 1

csc (x) = 0 :

No Solution

csc (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

csc (θ) = 1.7824

- 22 cos (θ) = 2

cos (θ) = \frac{6}{2}

x, - sin (0.6 (x + y)) \cdot 0.6 + 0.25 = 0

5 sin (60 t) = 0

What is the general solution for cot^2(x)+csc(x)+1=0 ?
The general solution for cot^2(x)+csc(x)+1=0 is x=(3pi)/2+2pin